x=(x^2+x)/40=((x*x*x)-x^2)/41+(x*x*x*x*x*x*x*)+2

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Solution for x=(x^2+x)/40=((x*x*x)-x^2)/41+(x*x*x*x*x*x*x*)+2 equation: 



x=(x^2+x)/40=((x*x*x)-x^2)/41+(x*x*x*x*x*x*x*)+2

We move all terms to the left:

x-((x^2+x)/40)=0

We multiply all the terms by the denominator


x*40)-((x^2+x)=0

Wy multiply elements

40x^2=0

a = 40; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·40·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{80}=0$

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